SKEMA Kertas 3 : PAT Tingkatan 4

*Jawapan yang disediakan ini adalah yang dapat memberikan SKOR 3 sahaja.

(a) Time(min)       The rise sucrose level(ml)

         0                            0.0

        10                           4.5

        20                           9.5

        30                           9.9

(bi)  Observations - Sample Answers :

      1-The first 10 minutes, the sucrose solution level is 4.5ml.

      2-At the 20th minutes, the sucrose solution level is 9.5ml.

      3-At the 30th minutes, the sucrose solution level is 9.9ml.

(bii) Inference - Sample Answers :

      1-At the 10th minute, water molecules diffuse through the 

          Visking tubing due to osmosis process.

      2-At the 20th minute, water molecules diffuse through the 

          Visking tubing due to osmosis process.

      3-At the 30th minute, water molecules diffuse through the 

          Visking tubing due to osmosis process.

(c) *same answer as (a); in table form

(d) Variables :

     Variables                Particulars to be implemented

     Manipulated :     The reading are taken at the different intervals//

     Time                  The reading are taken at 10 minutes intervals

      Responding :      Measuare and record the rise in the sucrose 

      The rise in         solution level by using the scale on the glass

      the sucrose        tube.

      solution level

     Constant :           Using the same concentration of sucrose

     Sucrose              solution //

     concentration//

     Volume of         Using the same volume of distilled water

     distilled water  

    

(e) Hypothesis - Sample Answers :

     1-The longer the time taken, the higher the level of sucrose

         solution(in the scaled glass tube)

     2-The shorter the time, the higher the level of sucrose solution 

        (in the scaled glass tube)

     3-If the time taken is shorter, the level of sucrose solution in the 

        scaled glass tube is less.

(f) Interpreting Data - Sample Answers :

    [The level of sucrose solution increases with time.]

    This is [because water molecules from outside the Visking tubing 

    diffuse through the semi permeable Visking tubing] [by osmosis 

    process.]

(g) Predicting - Sample Answers : (either answer 1 or answer 2)

     1-[The level of sucrose solution in scaled glass tube increases

         more than 9.9ml] because [water molecules diffuse through

         the semi-permeable Visking tubing] [by osmosis process.]

     2-[There is no increase in the level of sucrose solution in the 

        scaled glass tube] because [the dynamic equilibrium has

        achieved.] The level of sucrose solution in the scaled glass

        tube is 9.9ml [because the net movement of water molecules

        in and out of the membrane is the same.]

(h) Defining by Operation - Sample Answers :

     1-Osmosis is a process where water molecules enter the Visking 

         tubing at the 10th minute and the level of sucrose solution in 

         the scaled glass tube is raised at 4.5ml.

     2-Osmosis is a process where water molecules enter the Visking 

         tubing at the 20th minute and the level of sucrose solution in 

         the scaled glass tube is raised at 9.5ml.

     3-Osmosis is a process where water molecules enter the Visking 

         tubing at the 30th minute and the level of sucrose solution in 

         the scaled glass tube is raised at 9.9ml.

(i) Classifying :

  

       Material                       Picture

  Distilled water                       C

 15% sucrose solution             A

 20% sucrose solution          B and D