SKEMA Kertas 3 : PAT Tingkatan 4

*Jawapan yang disediakan ini adalah yang dapat memberikan SKOR 3 sahaja.

(a) Time(min)       The rise sucrose level(ml)

         0                            0.0

        10                           4.5

        20                           9.5

        30                           9.9

(bi)  Observations - Sample Answers :

      1-The first 10 minutes, the sucrose solution level is 4.5ml.

      2-At the 20th minutes, the sucrose solution level is 9.5ml.

      3-At the 30th minutes, the sucrose solution level is 9.9ml.

(bii) Inference - Sample Answers :

      1-At the 10th minute, water molecules diffuse through the 

          Visking tubing due to osmosis process.

      2-At the 20th minute, water molecules diffuse through the 

          Visking tubing due to osmosis process.

      3-At the 30th minute, water molecules diffuse through the 

          Visking tubing due to osmosis process.

(c) *same answer as (a); in table form

(d) Variables :

     Variables                Particulars to be implemented

     Manipulated :     The reading are taken at the different intervals//

     Time                  The reading are taken at 10 minutes intervals

      Responding :      Measuare and record the rise in the sucrose 

      The rise in         solution level by using the scale on the glass

      the sucrose        tube.

      solution level

     Constant :           Using the same concentration of sucrose

     Sucrose              solution //

     concentration//

     Volume of         Using the same volume of distilled water

     distilled water  

    

(e) Hypothesis - Sample Answers :

     1-The longer the time taken, the higher the level of sucrose

         solution(in the scaled glass tube)

     2-The shorter the time, the higher the level of sucrose solution 

        (in the scaled glass tube)

     3-If the time taken is shorter, the level of sucrose solution in the 

        scaled glass tube is less.

(f) Interpreting Data - Sample Answers :

    [The level of sucrose solution increases with time.]

    This is [because water molecules from outside the Visking tubing 

    diffuse through the semi permeable Visking tubing] [by osmosis 

    process.]

(g) Predicting - Sample Answers : (either answer 1 or answer 2)

     1-[The level of sucrose solution in scaled glass tube increases

         more than 9.9ml] because [water molecules diffuse through

         the semi-permeable Visking tubing] [by osmosis process.]

     2-[There is no increase in the level of sucrose solution in the 

        scaled glass tube] because [the dynamic equilibrium has

        achieved.] The level of sucrose solution in the scaled glass

        tube is 9.9ml [because the net movement of water molecules

        in and out of the membrane is the same.]

(h) Defining by Operation - Sample Answers :

     1-Osmosis is a process where water molecules enter the Visking 

         tubing at the 10th minute and the level of sucrose solution in 

         the scaled glass tube is raised at 4.5ml.

     2-Osmosis is a process where water molecules enter the Visking 

         tubing at the 20th minute and the level of sucrose solution in 

         the scaled glass tube is raised at 9.5ml.

     3-Osmosis is a process where water molecules enter the Visking 

         tubing at the 30th minute and the level of sucrose solution in 

         the scaled glass tube is raised at 9.9ml.

(i) Classifying :

  

       Material                       Picture

  Distilled water                       C

 15% sucrose solution             A

 20% sucrose solution          B and D

 

Medan Biologi SPM (klik sini)

PEPERIKSAAN PERCUBAAN 2007 SPM

KERTAS 1

1) D
2) B
3) D
4) B
5) D
6) C
7) B
8) D
9) B
10) B
11) B
12) C
13) B
14) B
15) C
16) A
17) C
18) D
19) B
20) B
21) C
22) B
23) B
24) B
25) B
26) A
27) A
28) A
29) A
30) C
31) D
32) C
33) D
34) B
35) C
36) B
37) C
38) C
39) A
40) A
41) A
42) B
43) C
44) B
45) D
46) D
47) D
48) C
49) A
50) A

BIOLOGI PERCUBAAN SPM 2007

1) B
2) A
3) B
4) C
5) C
6) B
7) B
8) A
9) C
10) A
11) C
12) B
13) D
14) B
15) A
16) C
17) C
18) D
19) B
20) C
21) D
22) D
23) A
24) A
25) A
26) A
27) C
28) A
29) D
30) C
31) B
32) A
33) A
34) D
35) A
36) A
37) C
38) C
39) A
40) A
41) D
42) D
43) D
44) B
45) C
46) B
47) A
48) B
49) C
50) C

PEPERIKSAAN PERCUBAAN SETARA SPM 2008

1) A
2) A
3) A
4) B
5) B
6) A
7) C
8) C
9) D
10) B
11) B
12) C
13) A
14) C
15) C
16) B
17) C
18) C
19) D
20) A
21) C
22) A
23) D
24) D
25) D
26) C
27) B
28) C
29) B
30) C
31) C
32) B
33) C
34) D
35) A
36) A
37) C
38) A
39) D
40) A
41) C
42) D
43) A
44) B
45) D
46) D
47) D
48) B
49) A
50) B

PEPERIKSAAN PERCUBAAN SPM 2009

1) C 26) D
2) D 27) A
3) C 28) D
4) B 29) C
5) D 30) C
6) C 31) B
7) D 32) B
8) A 33) A
9) B 34) D
10) B 35) B
11) D 36) A
12) B 37) D
13) C 38) A
14) A 39) D
15) B 40) C
16) C 41) A
17) D 42) C
18) C 43) D
19) B 44) C
20) A 45) A
21) D 46) B
22) B 47) A
23) A 48) B
24) C 49) D
25) B 50) A

Skema Jawapan Ujian 1 Tkn 4

PART A (OBJECTIVE QUESTION)

ANSWER :

1. C 11.C

2. B 12.C

3. D 13.D

4. D 14.A

5. B 15.B

6. A 16.C

7. A 17.C

8. B 18.B

9. A 19.D

10.D 20.B

PART B (STRUCTURED QUESTION)

1. a) K = liver

L = stomach 4 correct – 2 m

M = duodenum 2 or 3 correct – 1 m

N = ileum (small intestine – REJECT) 1 only correct – 0 m

b) Cell à Tissue à Organ à System à Organism -------------------------- 1 m

c) Shoot system --------------------------------------------------------------------- 1m

List the organ : leaf / flower / bud / stem / shoot / fruit ------ (any 2) ---- 2 m

OR

Root system ---------------------------------------------------------------------- 1 m

List the organ : root / root hair ------------------------------------------------ 2 m

d) i) Nervous system / Integumentary system /

Circulatory system / Muscular system /

Endocrine system ----------------------------------------- (any 2) ---- 2 m

ii) Nervous system – detect the changes(increases or decreases) of

temperature.

Integumentary system – stop or increase sweating process.

Circulatory system – blood vessel(arteriole) will either constrict

(vasoconstriction) or dilate(vasodilation).

Muscular system – hair erector muscle will either contract to raise the

hairs or relax to lower the hairs.

Endocrine system – secrete more or less adrenaline / thyroxine hormone.

* any 2 correct explanation ------------- 2 m

2. a) X = phospholipid bilayer ------------------------------------------- 1 m

Y = carrier protein --------------------------------------------------- 1 m

Z = pore / channel protein ------------------------------------------ 1 m

b) i) 1. hydrophilic head ------------------------------------------------------------ 1 m

2. hydrophobic tail ------------------------------------------------------------ 1 m

ii) Characteristic : semi permeable / selectively permeable membrane ---- 1 m

Explanation : a membrane that allows only certain molecules /

substances / particles to pass through it -------------------- 1 m

iii) Main function :

Acts as a barrier between the internal & external environment of the cell //

Allows only specific molecules to pass through it //

Provide the structural basis for all cell membrane -------(any 1) --------- 1 m

c) i) Simple diffusion ----------------------------------------------------------------- 1 m

ii) Example :

· F1 : Gasses exchange at alveolus / body cells/tissues ---------------- 1 m

P1 - Oxygen that is in higher concentration at the alveolus

compare to in the blood capillary,

P2 - (so) Oxygen will diffuse from the alveolus to the blood

capillary.

P3 - Carbon dioxide that is more concentrated in the blood

capillary compare to in the alveolus

P4 - (so) Carbon dioxide will diffuse from the blood capillary to

the alveolus

F1 + any 2P --------------------------------------------------------------- 2 m

3 m

* similar explanation for at body cell/tissue

· F2 : Gasses exchange in unicellular organism ------------------------ 1 m

P1 - Oxygen is higher concentration in the water / surrounding

compare to in the Amoeba sp. / Paramecium sp. / unicellular

organism

P2 - (so) Oxygen will diffuse from the water into Amoeba sp. /

Paramecium sp. /the unicellular organism

P3 - Carbon dioxide is higher concentration in the Amoeba sp. /

Paramecium sp. / unicellular organism compare to in the

water / surrounding

P4 - (so) Carbon dioxide will diffuse from the Amoeba sp. /

Paramecium sp. / unicellular organism to the water /

surrounding

F2 + any 2P --------------------------------------------------------------- 2 m

3 m

PART C (ESSAY QUESTION)

1. i)

Amoeba sp.	Structure / Living processes	Paramecium sp.
Present	Pseudopodium	Absent
One	Number of contractile vacuole	Two
Absent	Cilia / Cillium	Present
One	Number of nucleus	Two / Micronucleus & macronucleus
With the help of pseudopodium	Movement / Locomotion	With the help of the cillium
Binary Fission or form spores when it’s in unfavourable condition	Reproduction	Binary Fission or conjugation when it’s in unfavourable condition

* any 4 correct differences ------------------------------ 4 marks

ii)

· Situation 1(S1) : Plant is not enough water ------------------------ 1mark

P1 – Transpiration is higher than water absorption -------------- 1 mark

P2 – More water molecules will diffuse out from stomata ------ 1 mark

3 marks

· Situation 2(S2) : Ecessive fertilizer given to the plant ----------- 1 mark

P1 – The soil becomes hypertonic // Root hair cell becomes hypotonic,

due to ecessive fertilizer. --------------------------------------- 1 mark

P2 – Water molecules will diffuse out from the root hair cells to the

soil ---------------------------------------------------------------- 1 mark

P3 – by / due to / via OSMOSIS ------------------------------------ 1 mark

* S2 + any 2P = 3 marks